(5)=4x^2-5x+10

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Solution for \(5)=4x^2-5x+10 equation: 



(5)=4x^2-5x+10

We move all terms to the left:

(5)-(4x^2-5x+10)=0

We get rid of parentheses

-4x^2+5x-10+5=0

We add all the numbers together, and all the variables

-4x^2+5x-5=0

a = -4; b = 5; c = -5;
Δ = b2-4ac
Δ = 52-4·(-4)·(-5)
Δ = -55
Delta is less than zero, so there is no solution for the equation

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